a=-2,求val("a")=?,val(a)=?说明原因.

a=-2,求val(a)=?,val(a)=?说明原因. c = Val(Mid(a,j, int val = ((a+b) + abs(a-b))/2; // val是 max 还是 min 这是什么东西. 在VB中 a=”zpg96daq”,则 Val (a) vb中定义什么类型的数据,自动保留2位小数,a = Val(Trim(MSFlexGrid1.TextMatrix(1,3))) / Val(Trim(MSFlexGrid1.TextMatrix(10,3))) * 100b = Val(Trim(MSFlexGrid1.TextMatrix(2,3))) / Val(Trim(MSFlexGrid1.TextMatrix(10,3))) * 100c = Val(Trim(M a=val(thisform.text1.value)在vfp中是什么意思 设A=12345678,则Val(left(A,4)+mid(A,4,2))=? Private Sub Command1_Click() A = Val(Text1.Text):B = Val(Text2.Text) For M = A To B M = M + 1 NextPrivate Sub Command1_Click()A = Val(Text1.Text):B = Val(Text2.Text)For M = A To BM = M + 1Next MLabel1 = MEnd Sub当A为1,B为2时,运行出来为什么 select a.* from test a where 1 > (select count(*) from test where name = a.name and val > a.val )sql语句,按name分组显示最大的val值的字段,不明白具体意思, 已知A$=abcdefgh 则表达式Val(Mid(A,2,3)+Mid(A,4,2))值为.麻烦看到后速回~ 【单选题】已知A$=”12345678” 则表达式Val(Left$(A$,4)+Mid(A$,4,2))的值为（ ） 已知A$=4567124 ,表达式val(mid(A,2,3) + right(A,3))的值是______. ((val)=((val)&15) + ((val)>>4)*10)是什么意思?如题 我想知道的是(val)&15和(val)>>4是什么意思,时设置系统时钟的一个宏定义 输入一元二次方程ax2+bx+c=0系数a,b,c的值,计算并输出一元二次方程的两个根x1和x2.Private Sub Command1_Click()Dim a%,b%,c%,,x1!,x2!a = Val(Text1)b = Val(Text2)c = Val(Text3)d = b ^ 2 - 4 * a * cIf d >= o Thenx1 = (-b + d ^ 1 / VB编程,一元二次方程a*x^2+b*x+c=0的根Dim a As Double Dim b As Double Dim c As Double Dim delta As Double Dim x1 As Double Dim x2 As Double a = Val(Text1.Text) b = Val(Text2.Text) c = Val(Text3.Text) delta = b * b - VB求三角形面积,结果老是为零,帮忙看以下代码.Private Sub Text1_Change()a = Val(Text1)End SubPrivate Sub Text2_Change()b = Val(Text2)End SubPrivate Sub Text3_Change()c = Val(Text3)End SubPrivate Sub Command1_Click()Label1 = Sqr(s * (s 如何用vb设计计算二次方程的根的程序Private Sub Command1_Click()Dim a As Single,b As Single,c As Single,d As Singlea = Val(Text1.Text)b = Val(Text2.Text)c = Val(Text3.Text)d = b ^ 2 - 4 * a * cIf d > 0 ThenLabel8.Caption = (-b + Sqr(d)) vb解二次函数代码问题!代码如下Private Sub Command1_Click()Dim a As Single,b As Single,c As SingleDim n As Single,m As Singlea = Val(Text1.Text)b = Val(Text2.Text)c = Val(Text3.Text)If b ^ 2 - 4 * a * c < 0 ThenLabel3.Caption = 无解Els