(cos10+根号3cos100)/sin20=?

(cos10+根号3cos100)/sin20=?
(cos10+根号3cos100)/sin20=?

(cos10+根号3cos100)/sin20=?
(cos10°+√3cos100°)/sin20°
=(cos10°-√3sin10°)/sin20°
=2((1/2)cos10°-(√3/2)sin10°)/sin20°
=2(sin30°cos10°-cos30°sin10°)/sin20°
=2sin(30°-10°)/sin20°
=2sin20°/sin20°
=2.

郭敦顒回答：
[cos10°+（√3）cos100°)]/sin20°=[0.98481－0.30077]/0.34202
=068404/0.34202
=2。