x^2+(x-2)^2-(2-x)^2+(x-1)^3+(1-x)^3=( )x^2+(x-2)^2-(2-x)^2+(x-1)^3+(1-x)^3=( )

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/29 03:49:09
x^2+(x-2)^2-(2-x)^2+(x-1)^3+(1-x)^3=( )x^2+(x-2)^2-(2-x)^2+(x-1)^3+(1-x)^3=( )

x^2+(x-2)^2-(2-x)^2+(x-1)^3+(1-x)^3=( )x^2+(x-2)^2-(2-x)^2+(x-1)^3+(1-x)^3=( )
x^2+(x-2)^2-(2-x)^2+(x-1)^3+(1-x)^3=( )
x^2+(x-2)^2-(2-x)^2+(x-1)^3+(1-x)^3=( )

x^2+(x-2)^2-(2-x)^2+(x-1)^3+(1-x)^3=( )x^2+(x-2)^2-(2-x)^2+(x-1)^3+(1-x)^3=( )
x^2+(x-2)^2-(2-x)^2+(x-1)^3+(1-x)^3
=x^2+(x-2)^2-(x-2)^2+(x-1)^3-(x-1)^3
=x^2

x^2+(x-2)^2-(2-x)^2+(x-1)^3+(1-x)^3=x^2

x^2+(x-2)^2-(2-x)^2+(x-1)^3+(1-x)^3
=x^2+(x-2+2-x)(x-2-2+x)+(x-1+1-x)[(x-1)^2-(x-1)(1-x)+(1-x)^2]
=x^2+0*(2x-4)+0*[(x-1)^2-(x-1)(1-x)+(1-x)^2]
=x^2