作业帮因式分解x³-4x²-12x 这样行不行?原式=x(x²-4x-12)=x(x²-4x+4-16)=x[(x-4)²-4²]=x(x-4+4)(x-4-4)=x²(x-8)
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/03 19:53:53
![因式分解x³-4x²-12x 这样行不行?原式=x(x²-4x-12)=x(x²-4x+4-16)=x[(x-4)²-4²]=x(x-4+4)(x-4-4)=x²(x-8)](/uploads/image/z/2982960-0-0.jpg?t=%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3x%26%23179%3B-4x%26%23178%3B-12x+%E8%BF%99%E6%A0%B7%E8%A1%8C%E4%B8%8D%E8%A1%8C%3F%E5%8E%9F%E5%BC%8F%3Dx%28x%26%23178%3B-4x-12%29%3Dx%28x%26%23178%3B-4x%2B4-16%29%3Dx%5B%28x-4%29%26%23178%3B-4%26%23178%3B%5D%3Dx%28x-4%2B4%29%28x-4-4%29%3Dx%26%23178%3B%28x-8%29)
因式分解x³-4x²-12x 这样行不行?原式=x(x²-4x-12)=x(x²-4x+4-16)=x[(x-4)²-4²]=x(x-4+4)(x-4-4)=x²(x-8)
因式分解x³-4x²-12x 这样行不行?
原式=x(x²-4x-12)
=x(x²-4x+4-16)
=x[(x-4)²-4²]
=x(x-4+4)(x-4-4)
=x²(x-8)
因式分解x³-4x²-12x 这样行不行?原式=x(x²-4x-12)=x(x²-4x+4-16)=x[(x-4)²-4²]=x(x-4+4)(x-4-4)=x²(x-8)
原式=x(x²-4x-12)
=x(x²-4x+4-16)
下一步错了
=x[(x-2)²-4²]
=x(x-2+4)(x-2-4)
=x(x+2)(x-6)
最后错了
=x(x²-4x+4-16)
=x[(x-2)²-4²]
=x(x-2+4)(x-2-4)
=x(x+2)(x-6)