作业帮求函数y=sinx+根号3cosx在区间[-π/2,π/2]上的最大值与最小值
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![求函数y=sinx+根号3cosx在区间[-π/2,π/2]上的最大值与最小值](/uploads/image/z/350803-19-3.jpg?t=%E6%B1%82%E5%87%BD%E6%95%B0y%3Dsinx%2B%E6%A0%B9%E5%8F%B73cosx%E5%9C%A8%E5%8C%BA%E9%97%B4%5B-%CF%80%2F2%2C%CF%80%2F2%5D%E4%B8%8A%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E4%B8%8E%E6%9C%80%E5%B0%8F%E5%80%BC)
求函数y=sinx+根号3cosx在区间[-π/2,π/2]上的最大值与最小值
求函数y=sinx+根号3cosx在区间[-π/2,π/2]上的最大值与最小值
求函数y=sinx+根号3cosx在区间[-π/2,π/2]上的最大值与最小值
y=2(sinxcosπ/3+cosxsinπ/3)
=2sin(x+π/3)
x=π/6属于[-π/2,π/2],ymax=2
x=-π/2属于[-π/2,π/2],ymin=sin(-π/6)=-1/2