化简sin(-11π/3)+cos(12π/5)tan2π-sec13π/5cot(-5π/2)

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/03 04:32:47
化简sin(-11π/3)+cos(12π/5)tan2π-sec13π/5cot(-5π/2)

化简sin(-11π/3)+cos(12π/5)tan2π-sec13π/5cot(-5π/2)
化简sin(-11π/3)+cos(12π/5)tan2π-sec13π/5cot(-5π/2)

化简sin(-11π/3)+cos(12π/5)tan2π-sec13π/5cot(-5π/2)
tan2π=0 cot(-5π/2)=0

sin(-11π/3)+cos(12π/5)tan2π-sec13π/5cot(-5π/2)
=sin(-11π/3)
=sin(-4π+π/3)
=sinπ/3
=√3/2

化简:sin(2π-α)cos(π+α)cos(11π/2-α)/cos(π-α)sin(3π-α)sin(-π-α)sin(9π/2+α) 化简:sin(2π-a)cos(π+a)cos(π/2+a)cos(11π/2-a)/cos(π-a)sin(3π-a)sin(-π-a)sin(9π/2+a) 化简sinπ/12-√3cosπ/12化简sinπ/12-√3cosπ/12 化简:[sin(2π-a)cos(π+a)cos(π/2+a)cos(11π/2-a)[sin(2π-a)cos(π+a)cos(π/2+a)cos(11π/2-a)]/[cos(π-a)sin(3π-a)sin(-π-a)sin(9π/2+a)] (1+sinα+cosα)*[sin(α/2)-cos(α/2)]/√(2+2cosα)化简 (3/2*π 化简sin(-π/2-α)sin(πα)cos(-α-π)/cos(π-α)sin(3π α) 化简 sin(2π-a)sin(π+a)cos-π-a) / sin(3π-a)cos(π-a) 化简:[sin(π+3α)cos(-α+3π)sin(α-3π/2)cos(11π/2-α)]÷[cos(3α+9π/2)sin(-α-π) 化简:[sin( π -a) cos( π+a)cos(3/2 π+a )]/cos(3 π-a )sin(3 π+a )sin(5/2 π-a ) 化简sin(α-5π)/cos(3π-α)×cos(π/2-α)/sin(α-3π)×cos(8π-α)/sin(-α-4π) 化简:[sin(π+3α)cos(-α+3π)sin(α-3π/2)cos(11π/2-α)]÷[cos(3α+9π/2)sin(-α-π)化简:[sin(π+3α)cos(-α+3π)sin(α-3π/2)cos(11π/2-α)] ÷ [cos(3α+9π/2)sin(-α-π)tan(-π+α)tan(π/2-α)] 化简sin(α-2π)+sin(-a-3π)cos(α-3π)/cos(π-α)-cos(-π-α)cos(α-4π) 化简sin(25π/12)cos(11π/6)-cos(11π/12)sin(5π/6)的值是 化简:cos(π-α)·sin(-π-α) / cos(11/2π-β)·tan(3π+β)RT、quickly~ 化简:1,cosπ/8的4次方- sinπ/8的4次方 2,sinπ/12-√3cosπ/12 化简sin(π+a)cos(π-a)tana/cos(π/2+a)sina 求值,若sinθ+2cosθ=0.求3sinθ-2cosθ/2cosθ-...化简sin(π+a)cos(π-a)tana/cos(π/2+a)sina求值,若sinθ+2cosθ=0.求3sinθ-2cosθ/2cosθ-sinθ的值要详细的过程在线 化简cos(3/2π+π)sin(-π+α) 化简√1-2sin(π-3)cos(π+3)