问已知|ab-2|与|b-1|互为相反数,试求代数式:ab分之1+(a+1)(b+1)分之1+（a+2)(b+2)分之1+·······+

问已知|ab-2|与|b-1|互为相反数,试求代数式:ab分之1+(a+1)(b+1)分之1+（a+2)(b+2)分之1+·······+
问已知|ab-2|与|b-1|互为相反数,试求代数式:ab分之1+(a+1)(b+1)分之1+（a+2)(b+2)分之1+·······+

问已知|ab-2|与|b-1|互为相反数,试求代数式:ab分之1+(a+1)(b+1)分之1+（a+2)(b+2)分之1+·······+
互为反数,则均为0,则b=1,a=2