y=sin(u-v)-cos(u+v) 求dy 用u,v,du,dv表示

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y=sin(u-v)-cos(u+v) 求dy 用u,v,du,dv表示

y=sin(u-v)-cos(u+v) 求dy 用u,v,du,dv表示
y=sin(u-v)-cos(u+v) 求dy 用u,v,du,dv表示

y=sin(u-v)-cos(u+v) 求dy 用u,v,du,dv表示
∂y/∂u=cos(u-v)+sin(u+v)
∂y/∂v=-cos(u-v)+sin(u+v)
所以dy=[cos(u-v)+sin(u+v)]du+[-cos(u-v)+sin(u+v)]dv

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