log(2)1/25乘以log(3)1/8乘以log(5)1/9
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log(2)1/25乘以log(3)1/8乘以log(5)1/9
log(2)1/25乘以log(3)1/8乘以log(5)1/9
log(2)1/25乘以log(3)1/8乘以log(5)1/9
log(2)1/25乘以log(3)1/8乘以log(5)1/9
=-2log(2)5*3log(3)2*log(5)3
=-12*ln5/ln2*ln2/ln3*ln3/ln5
=-12
原式=(-2lg5/lg2)×(-3lg2/lg3)×(-2lg3/lg5)
=-12
用换底公式
原式=lg(1/25)/lg(2) * lg(1/8)/lg(3) * lg(1/9)/lg(5)
=[-2lg(5)/lg(2)]*[-3lg(2)/lg(3)]*[-2(3)/lg(5)]
=-2*(-3)*(-2)=-12
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