[x÷35+(2x-14）÷28)]-[ x÷28+(2x-14）÷35]= 12÷60 怎么算,

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[x÷35+(2x-14）÷28)]-[ x÷28+(2x-14）÷35]= 12÷60 怎么算,
[x÷35+(2x-14）÷28)]-[ x÷28+(2x-14）÷35]= 12÷60 怎么算,

[x÷35+(2x-14）÷28)]-[ x÷28+(2x-14）÷35]= 12÷60 怎么算,
两边同乘以35*28,并去括号得：
28x+70x-35*14-35x-56x+28*14=35*28*12/60
7x-7*14=35*28*12/60
x-14=140*12/60
x=42

[x÷35+(2x-14）÷28)]-[ x÷28+(2x-14）÷35]= 12÷60
x/35+(2x-14)/28-x/28-(2x-14)/35=1/5
x/35+x/14-1/2-x/28-2x/35+2/5=1/5
(x+2x)/35+...

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[x÷35+(2x-14）÷28)]-[ x÷28+(2x-14）÷35]= 12÷60
x/35+(2x-14)/28-x/28-(2x-14)/35=1/5
x/35+x/14-1/2-x/28-2x/35+2/5=1/5
(x+2x)/35+(x+2x)/28=1/5-2/5+1/2
4(3x)/140+5(3x)/140=3/10
27x=42
x=42/27

收起

(x/35+x/14-1/2)-(x/28+2x/35-2/5)=1/5
(1/10)x-1/2-(13/140)x+2/5=1/5
x/140=3/10
x=42

将原式化简后得到如下：(14-x)/35+(x-14)/28=1/5
等式两边同乘以980化简后得到7x=294,x=42 解毕

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