解方程(x+1/x-1)+(x-2/x+2)+(x-3/x+3)+(x+4/x-4)=4

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/28 07:17:55
解方程(x+1/x-1)+(x-2/x+2)+(x-3/x+3)+(x+4/x-4)=4

解方程(x+1/x-1)+(x-2/x+2)+(x-3/x+3)+(x+4/x-4)=4
解方程(x+1/x-1)+(x-2/x+2)+(x-3/x+3)+(x+4/x-4)=4

解方程(x+1/x-1)+(x-2/x+2)+(x-3/x+3)+(x+4/x-4)=4
(x+1/x-1)+(x-2/x+2)+(x-3/x+3)+(x+4/x-4)=4,
——》1+2/(x-1)+1-4/(x+2)+1-6/(x+3)+1+8/(x-4)=4,
——》1/(x-1)+4/(x-4)=2/(x+2)+3/(x+3),
——》(5x-8)/(x^2-5x+4)=(5x+12)/(x^2+5x+6)
——》去分母整理得:5x^2+5x-16=0,
——》x=(-5+-√345)/10.

先把方程化成:1+2/(x-1)+1-4/(x+2)+1-6/(x+3)+1+8/(x-4)=4,
即2/(x-1)-4/(x+2)-6/(x+3)+8/(x-4)=0,
1/(x-1)+4/(x-4)=2/(x+2)+3/(x+3),
(5x-8)/(x-1)(x-4)=(5x+12)/(x+2)(x+3),通分,
(5x-8)(x+2)(x+3)=(5x+12)...

全部展开

先把方程化成:1+2/(x-1)+1-4/(x+2)+1-6/(x+3)+1+8/(x-4)=4,
即2/(x-1)-4/(x+2)-6/(x+3)+8/(x-4)=0,
1/(x-1)+4/(x-4)=2/(x+2)+3/(x+3),
(5x-8)/(x-1)(x-4)=(5x+12)/(x+2)(x+3),通分,
(5x-8)(x+2)(x+3)=(5x+12)(x-1)(x-4),即5x^3+17x^2-10x-48=5x^3-13x^2-40x+48
即5x^2+5x-16=0;解得x1=-1/2+(1/10)*sqrt(345), x2=-1/2-(1/10)*sqrt(345)

收起