(1+sinx)^2=cos^2x是不是对的,怎么转过来的

y=(1+sinx)/cosx,求导是不是等于（sinx+1）/(cos^2)x (1+sinx)^2=cos^2x是不是对的,怎么转过来的 y=(2sinx-1)/(sinx+3)和y=cos^2x+sinx的值域 cos 2x=1-2 sinx 要解x y=cos^2x+sinx+1(|x| 求函数f(x)=cos^2x+sinx-1 sinx+cos∧2x=1求x f(sinx)=1+cos(2x),求f(x), f(sinx+1/sinx)=csc^2x-cos^2x 求f(x) 若 f(sinx+1/sinx)=csc^2x-cos^2x,求f(x) y=2cos^2 x+sinx ∫(1+sinx) / cos^2 x dx -sinx=cos((3π/2-x)从-sinx推导 若sinx+sin^2x=1,则cos^2x+cos^4x=?由 sinx+sin^2x=1得 sinx=1-sin^2x=cos^2xcos^2x+cos^4x=cos^2x(1+cos^2x)=sinx(1+sinx)=sinx+sin^2x=1cos^2x(1+cos^2x)=sinx(1+sinx)怎么来的? 若sinx+sin^2x=1,则cos^2x+cos^4x=? f（1+sinX）=2+cos^2X sinX=1/3 ,cos(2X - π)= 若sinx+sin^2x=1,则cos^2x-sinX=?急...