已知(x+y)(x+y-10)+25=0,且x-y=3,求x,y的值

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已知(x+y)(x+y-10)+25=0,且x-y=3,求x,y的值

已知(x+y)(x+y-10)+25=0,且x-y=3,求x,y的值
已知(x+y)(x+y-10)+25=0,且x-y=3,求x,y的值
 

已知(x+y)(x+y-10)+25=0,且x-y=3,求x,y的值
由题得:
(x+y)(x+y-10)+25=0 ----(1) 且 x-y=3 ----(2)
由(1)得:
(x+y)^2-10(x+y)+25=0
((x+y)-5)^2=0
(x+y)-5=0
x+y=5 ----(3)
(3)+(2)得
2x=8
x=4 代入(3)得y=1
所以原题的解为:
x=4 y=1