若x.y满足y=√1-3x+√(x-1)²+√3x-1,求x+y的平方根.

已知实数x,y,满足x-√x-1=√y+3-y,则x+y最大值是? 若变量x,y满足约束条件{x>=-1;y>=x;3x+2y 变量x,y满足约束条件,x+y>=3,x-y>=-1,2x-y 若实数x,y满足x的平方+2√3x+根号（x+y+1）+3=0,求代数式(1/x-y+1/x+y)÷y/（x²+y²）重点是代入部分啊 若x,y 满足条件{x>=1 y>=1 x+y-3 若x.y满足y=√1-3x+√(x-1)²+√3x-1,求x+y的平方根. 若实数x,y满足不等式x-y>=-1,x+y>=1,3x-y 若实数x,y满足不等式x-y>=-1,x+y>=1,3x-y 若x,y满足|2x-y-3|+|3x+2y+1|=0,则x= y= 若x,y满足约束条件,x>=0,y>=0,x-y>=-1,3x+4y 若x,y满足|x-y+1|+(x+y+3)^2=0则x^2-y^2= 若x,y是实数,满足√1-3x+√3x-1+y=6,则xy= 若实数x,y满足x-y+1》=0,x+y>=0,x 若实数x,y满足x-y+1>=0,x+y>=0,x 设x.y满足条件y>=0.X-Y+1>=0.x+y-3 若x、y满足2x+y=6,x-3y=1,求7y(x-3y)²-2(3y-x)³的值 已知x,y满足{x>=1,x+y 已知x,y满足{x>=1,x+y