arctan1/2+arctan1/5+arctan1/3
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arctan1/2+arctan1/5+arctan1/3
arctan1/2+arctan1/5+arctan1/3
arctan1/2+arctan1/5+arctan1/3
tana1=1/5,tana2=1/3 tana3=1/2 上式=a1+a2+a3
tan(a1+a2)=(tana1+tana2)/(1-tana1tana2)=4/7 a1+a2=arctan4/7 tan(a1+a2+a3)=[tan(a1+a2)+tana3]/(1-tan(a1+a2)tana3) =3/2 所以a1+a2+a3 =arctan(3/2)
arctan1/2+arctan1/5+arctan1/3
求证arctan1/2+arctan1/5+arctan1/8=pai/4
arctan1/3+arctan1/2+arctan1=几,
arctan1/3+arctan1/5+arctan1/7+arctan1/8如题
求值:arctan1/2+arctan1/3
arctan1/2+arctan1/5+arctan1/8=这个应该怎么算呢
求tan(arctan1/2+arctan1/3)
tan(arctan1/5+arctan3)
A=arctan1/2
arctan1/2+arctan1/3 解答题求解 谢谢
送分ing,求值:arctan1/2+arctan1/3.
tan(arctan1/5+arctan3)=
tan(90-2arctan1/2)
直线x=5与直线x+2y-6=0的夹角为( ) A.arctan1/2 B.π/2+arctan1/2 C.π/2-arctan1/2 D.π-arctan1/2
tan (arctan1/5+arctan3)的值等于
tan(1/2arctan1/2)=?
lim(x-->0-)arctan1/x 为什么趋于-2/ lim(x-->0+)arctan1/x 为什么趋于2/
arctan1等于多少