若sin(π/6-α)=a,则cos(2π/3-α)=多少帮个忙,

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若sin(π/6-α)=a,则cos(2π/3-α)=多少帮个忙,

若sin(π/6-α)=a,则cos(2π/3-α)=多少帮个忙,
若sin(π/6-α)=a,则cos(2π/3-α)=多少
帮个忙,

若sin(π/6-α)=a,则cos(2π/3-α)=多少帮个忙,
cos(2π/3-α)=cos(π/2+π/6-α)=-sin(π/6-α)=-a

sin(π/6-α)=a,所以cos〔π/2-(π/6-α)〕=a,即cos(π/3+α)=a,所以cos〔π-(π/3+α)〕=-a,即cos(2π/3-α)=-a

利用sinα=cos(π/2-α)这个公式,cos(2π/3-α)=cos【π/2-(α—π/6)】=sin(α-π/6)=-a

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